Answer
$\log _{a}\left( MN\right) =\log _{a}M+\log _{a}N$
Work Step by Step
From the properties of logarithms we get $\log _{a}\left( MN\right) =\log _{a}M+\log _{a}N$
Precalculus (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0-32197-907-9
ISBN 13:
978-0-32197-907-0
Chapter 5 - Exponential and Logarithmic Functions - 5.5 Properties of Logarithms - 5.5 Assess Your Understanding - Page 305: 4
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