Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 5 - Exponential and Logarithmic Functions - 5.5 Properties of Logarithms - 5.5 Assess Your Understanding - Page 305: 32



Work Step by Step

We know that $\log_a {x}-\log_a {y}=\log_a {\left(\frac{x}{y}\right)}$. Hence,, $\ln {0.5}=\ln{\frac{1}{2}}=\ln{1}-\ln{2}$ Note that $\ln {1}=0$. Thus, $\ln{1}-\ln{2} \\=0-\ln{2} \\=0-a \\=-a$
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