Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 5 - Exponential and Logarithmic Functions - 5.5 Properties of Logarithms - 5.5 Assess Your Understanding - Page 305: 56

Answer

$ln5+2lnx+\frac{1}{3}ln(1-x)-ln4-2ln(x+1)$

Work Step by Step

$ln\frac{5x^2\ \sqrt[3] {1-x}}{4(x+1)^2}=ln\frac{5x^2\ (1-x)^{1/3}}{4(x+1)^2}=ln5+2lnx+\frac{1}{3}ln(1-x)-ln4-2ln(x+1)$
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