Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 5 - Exponential and Logarithmic Functions - 5.2 One-to-One Functions; Inverse Functions - 5.2 Assess Your Understanding - Page 267: 82


domain: $(0,8)$ range: $[0,15]$

Work Step by Step

Since $g$ is one-to-one the domain of $g$ is the range of $g^{-1}$ and the range of $g$ is the domain of $g^{-1}$. Hence, $g^{-1}$ has: domain: $(0,8)$ range: $[0,15]$
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