## Precalculus (10th Edition)

Published by Pearson

# Chapter 5 - Exponential and Logarithmic Functions - 5.2 One-to-One Functions; Inverse Functions - 5.2 Assess Your Understanding: 79

#### Answer

domain: $[-2,\infty)$ range: $[5,\infty)$

#### Work Step by Step

Since $f$ is one-to-one the domain of $f$ is the range of $f^{-1}$ and the range of $f$ is the domain of $f^{-1}$. Hence $f^{-1}$ has: domain: $[-2,\infty)$ range: $[5,\infty)$

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