Answer
domain: $[5,\infty)$
range: $[0,\infty)$
Work Step by Step
Since $f$ is one-to-one the domain of $f$ is the range of $f^{-1}$ and the range of $f$ is the domain of $f^{-1}$.
Hence, $f^{-1}$ has:
domain: $[5,\infty)$
range: $[0,\infty)$