## Precalculus (10th Edition)

domain: $[0,\infty)$ range: $(-\infty,0]$
The domain of $g$ is the range of $g^{-1}$ and the range of $g$ is the domain of $g^{-1}$. Hence, the inverse function $g^{-1}$ has: domain: $[0,\infty)$ range: $(-\infty,0]$