Answer
(a) See graph.
(b) $(-\infty,-2)U(-2,\infty)$, $(-\infty,0)$
(c) $x=-2$, $y=0$
Work Step by Step
(a) To obtain the graph of $R(x)=\frac{-1}{x^2+4x+4}=\frac{-1}{(x+2)^2}$ from $y=\frac{1}{x^2}$, shift the curve 2 units to the right, then reflect across the x-axis. See graph.
(b) Based on the graph, we can find the domain as $(-\infty,-2)U(-2,\infty)$ and range as $(-\infty,0)$
(c) We can identify the vertical asymptote $x=-2$, horizontal asymptote $y=0$, or oblique asymptote $none$.
