Answer
(a) See graph.
(b) $(-\infty,-1)U(-1,\infty)$, $(-\infty,0)U(0,\infty)$
(c) $x=-1$, $y=0$
Work Step by Step
(a) To obtain the graph of $H(x)=\frac{-2}{x+1}$ from $y=\frac{1}{x}$, shift the curve 1 unit to the left, stretch the curve vertically by a factor of 2, then reflect across the x-axis. See graph.
(b) Based on the graph, we can find the domain as $(-\infty,-1)U(-1,\infty)$ and range as $(-\infty,0)U(0,\infty)$
(c) We can identify the vertical asymptote $x=-1$, horizontal asymptote $y=0$, or oblique asymptote $none$.
