Answer
(a) See graph.
(b) $(-\infty,-2)U(-2,\infty)$, $(0,\infty)$
(c) $x=-2$, $y=0$
Work Step by Step
(a) To obtain the graph of $G(x)=\frac{2}{(x+2)^2}$ from $y=\frac{1}{x^2}$, shift the curve 2 units to the right, then stretch the curve vertically by a factor of 2. See graph.
(b) Based on the graph, we can find the domain as $(-\infty,-2)U(-2,\infty)$ and range as $(0,\infty)$
(c) We can identify the vertical asymptote $x=-2$, horizontal asymptote $y=0$, or oblique asymptote $none$.
