Answer
All real numbers except $-3$ and $3$.
Work Step by Step
Note that $x^2-9=(x+3)(x-3).$
The denominator cannot be $0$.
Hence,
$x-3\ne0\longrightarrow x\ne 3$
$x+3\ne0\longrightarrow x\ne-3$
Thus, the domain is that set of all real numbers except $-3$ and $3$.