Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 14 - A Preview of Calculus: The Limit, Derivative, and Integral of a Function - 14.3 One-sided Limits; Continuous Functions - 14.3 Assess Your Understanding - Page 890: 42

Answer

$-1$

Work Step by Step

Factor each polynomial: $$\lim_{x\to ^+}\frac{x^3-x^2}{x^4+x^2}\\=\lim_{x\to 0^+}\frac{x^2(x-1)}{(x^2)(x^2+1)}.$$ Cancel the common factors: $$\lim_{x\to 0^+}\frac{(x-1)}{(x^2+1)}\\=\frac{0-1}{(0^2+1)}=-1$$
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