Answer
$4$
Work Step by Step
We do what we have to according to the exercise: $$\lim_{x\to 2^+}\frac{x^2-4}{x-2}=\lim_{x\to 2^+}\frac{(x+2)(x-2)}{x-2}=\lim_{x\to 2^+}(x+2)=2+2=4.$$
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