Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 14 - A Preview of Calculus: The Limit, Derivative, and Integral of a Function - 14.3 One-sided Limits; Continuous Functions - 14.3 Assess Your Understanding - Page 890: 41

Answer

$-\frac{2}{3}$

Work Step by Step

Factor each polynomial: $$\lim_{x\to -1^-}\frac{x^2-1}{x^3+1}\\=\lim_{x\to -1^-}\frac{(x+1)(x-1)}{(x+1)(x^2-x+1)}.$$ Cancel the common factors: $$\lim_{x\to -1^-}\frac{x-1}{(x^2-x+1)}\\=\frac{(-1)-1}{((-1)^2-(-1)+1)}=-\frac{2}{3}$$
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