Answer
$-\frac{2}{3}$
Work Step by Step
Factor each polynomial:
$$\lim_{x\to -1^-}\frac{x^2-1}{x^3+1}\\=\lim_{x\to -1^-}\frac{(x+1)(x-1)}{(x+1)(x^2-x+1)}.$$
Cancel the common factors: $$\lim_{x\to -1^-}\frac{x-1}{(x^2-x+1)}\\=\frac{(-1)-1}{((-1)^2-(-1)+1)}=-\frac{2}{3}$$