Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 14 - A Preview of Calculus: The Limit, Derivative, and Integral of a Function - 14.3 One-sided Limits; Continuous Functions - 14.3 Assess Your Understanding - Page 890: 40

Answer

$2$

Work Step by Step

Factor each polynomial: $$\lim_{x\to 1^-}\frac{x^3-1}{x-1}\\=\lim_{x\to 1^-}\frac{x(x-1)(x+1)}{x-1}.$$ Cancel the common factors: $$\lim_{x\to 1^-}x(x+1)\\=1(1+1)=2$$
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