Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 12 - Sequences; Induction; the Binomial Theorem - Chapter Review - Chapter Test - Page 840: 5


$\sum_{k=1}^{10} (-1)^k(\frac{k+1}{k+4})$

Work Step by Step

We can see that this is the sum of the $10$ fractions in which the first numerator is $2$, increases by $1$ in each term and in which the first denominator is $5$, increases by $1$ in each term. Also, the signs are alternating, starting with $-$. Hence the summation formula is: $\sum_{k=1}^{10} (-1)^k(\frac{k+1}{k+4})$
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