Chapter 12 - Sequences; Induction; the Binomial Theorem - Chapter Review - Chapter Test - Page 840: 1

$s_1=0$ $s_2=\frac{3}{10}$ $s_3=\frac{8}{11}$ $s_4=\frac{5}{4}$ $s_5=\frac{24}{13}$

If $\{s_n\}=\frac{n^2-1}{n+8}$, then $s_1=\frac{1^2-1}{1+8}=\frac{0}{9}=0$ $s_2=\frac{2^2-1}{2+8}=\frac{3}{10}$ $s_3=\frac{3^2-1}{3+8}=\frac{8}{11}$ $s_4=\frac{4^2-1}{4+8}=\frac{15}{12}=\frac{5}{4}$ $s_5=\frac{5^2-1}{5+8}=\frac{24}{13}$