Answer
$-8$
Work Step by Step
We know that for a matrix
\[
\left[\begin{array}{rr}
a & b \\
c &d \\
\end{array} \right]
\]
the determinant, $D=ad-bc.$
Hence here $D=xb-ay=8$ is given.
Our determinant is: $ay-xb=-(xb-ay)=-(8)=-8$
Precalculus (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0-32197-907-9
ISBN 13:
978-0-32197-907-0
Chapter 11 - Systems of Equations and Inequalities - Chapter Review - Review Exercises - Page 794: 33
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