Precalculus (10th Edition)

$\left\{\left(2,-1\right)\right\}$
We are given the system of equations: $\begin{cases} x-2y-4=0\\ 3x+2y-4=0 \end{cases}$ Bring the system to the standard form: $\begin{cases} x-2y=4\\ 3x+2y=4 \end{cases}$ Use the elimination method. Add the two equations to eliminate $y$ and find $x$: $x-2y+3x+2y=4+4$ $4x=8$ $x=2$ Substitute $x=2$ in the first equation of the given system and determine $y$: $x-2y=4$ $2-2y=4$ $2y=-2$ $y=-1$ The solution set is: $\left\{\left(2,-1\right)\right\}$