Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 11 - Systems of Equations and Inequalities - Chapter Review - Review Exercises - Page 794: 14

Answer

$\begin{bmatrix}6&0\\12&24\\-6&12\end{bmatrix}$

Work Step by Step

We are given the matrix: $A=\begin{bmatrix}1&0\\2&4\\-1&2\end{bmatrix}$ Compute $6A$: $6A=6\begin{bmatrix}1&0\\2&4\\-1&2\end{bmatrix}=\begin{bmatrix}6(1)&6(0)\\6(2)&6(4)\\6(-1)&6(2)\end{bmatrix}$ $=\begin{bmatrix}6&0\\12&24\\-6&12\end{bmatrix}$
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