Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 11 - Systems of Equations and Inequalities - Chapter Review - Review Exercises - Page 794: 19



Work Step by Step

We know that for a matrix \[ \left[\begin{array}{rr} a & b \\ c &d \\ \end{array} \right] \] the determinant $D$ is given by the formula $D=ad-bc.$ We also know that if $D=0$, then the matrix is singular. The given matrix has $D=(4\cdot2)-[(-8)\cdot(-1)]\\ D=8-8\\ D=0$ The square matrix has a determinant of zero therefore it is singular.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.