## Precalculus (10th Edition)

$\{(8,-4)\}$
We are given the system of equations: $\begin{cases} 3x=24\\ x+2y=0 \end{cases}$ Determine $x$ from the first equation: $x=\dfrac{24}{3}$ $x=8$ Determine $y$ using the second equation: $x+2y=0$ $8+2y=0$ $2y=-8$ $y=-4$ The solution set of the system is: $\{(8,-4)\}$