## Precalculus (10th Edition)

$[-3,2]$
We are given the inequality: $6-x\geq x^2$ Rewrite the inequality: $x^2+x-6\leq 0$ Factor: $x^2-2x+3x-6\leq 0$ $x(x-2)+3(x-2)\leq 0$ $(x-2)(x+3)\leq 0$ Solve the two linear equations: $x-2=0\Rightarrow x=2$ $x+3=0\Rightarrow x=-3$ The solution of the inequality is: $[-3,2]$