Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 10 - Analytic Geometry - Chapter Review - Cumulative Review - Page 701: 3



Work Step by Step

We are given the inequality: $6-x\geq x^2$ Rewrite the inequality: $x^2+x-6\leq 0$ Factor: $x^2-2x+3x-6\leq 0$ $x(x-2)+3(x-2)\leq 0$ $(x-2)(x+3)\leq 0$ Solve the two linear equations: $x-2=0\Rightarrow x=2$ $x+3=0\Rightarrow x=-3$ The solution of the inequality is: $[-3,2]$
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