Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 10 - Analytic Geometry - Chapter Review - Cumulative Review - Page 701: 1

Answer

$-6x-3h+5$

Work Step by Step

$\dfrac{f(x+h)-f(x)}{h}\\=\dfrac{(-3(x+h)^2+5(x+h)-2)-(-3x^2+5x-2)}{h}\\=\dfrac{(-3x^2-6xh-3h^2+5x+5h-2)-(-3x^2+5x-2)}{h}\\=\dfrac{-6xh-3h^2+5h}{h}\\=-6x-3h+5$
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