Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 10 - Analytic Geometry - Chapter Review - Cumulative Review - Page 701: 11


$22.5$ degrees

Work Step by Step

We are given the equation: $\cot (2\theta)=1,0\lt \theta\lt 90$ $\dfrac{1}{\tan (2\theta)}=1$ $\tan (2\theta)=1$ $0\lt \theta\lt 90$ $0\lt 2\theta\lt 180$ For $0\lt 2\theta\lt 180$, there is only one value of $\theta$ to fit the equation: $2\theta=45$ $\theta=22.5$
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