Answer
$1-2i$
Work Step by Step
Multiply the numerator and the denominator by the conjugate of $i$ which is $-i$.
$\dfrac{2+i}{i}=\dfrac{2+i}{i}\cdot \dfrac{-i}{-i}$
Use distributive property in the numerator.
$=\dfrac{-2i-i^2}{-i^2}$
Use $i^2=-1$.
$=\dfrac{-2i-(-1)}{-(-1)}$
Simplify.
$=\dfrac{-2i+1}{1}$
$=-2i+1$
$=1-2i$
Hence, the solution in the standard form is $1-2i$.
