Answer
$13+i$.
Work Step by Step
Use FOIL method.
$(5+3i)(2-i)=5\cdot 2-5\cdot i+3i\cdot 2-3i\cdot i$
Simplify.
$=10-5i+6i-3i^2$
$=10+i-3i^2$
Use $i^2=-1$.
$=10+i-3(-1)$
Simplify.
$=10+i+3$
$=13+i$
Hence, the solution in the standard form is $13+i$.
