Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Appendix A - Review - A.7 Complex Numbers; Quadratic Equations in the Complex Number System - A.7 Assess Your Understanding - Page A60: 19

Answer

$6+4i$

Work Step by Step

Use distributive property. $2i(2-3i)=2i\cdot 2-2i\cdot 3i$ Simplify. $=4i-6i^2$ Use $i^2=-1$. $=4i-6(-1)$ Simplify. $=4i+6$ $=6+4i$ Hence, the solution in the standard form is $6+4i$.
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