Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Appendix A - Review - A.7 Complex Numbers; Quadratic Equations in the Complex Number System - A.7 Assess Your Understanding - Page A60: 21

Answer

$10-5i$

Work Step by Step

Use FOIL method. $(3-4i)(2+i)=3\cdot 2+3\cdot i -4i\cdot 2-4i\cdot i$ Simplify. $=6+3i-8i-4i^2$ $=6-5i-4i^2$ Use $i^2=-1$. $=6-5i-4(-1)$ Simplify. $=6-5i+4$ $=10-5i$ Hence, the solution in the standard form is $10-5i$.
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