Answer
Volume of the closed right circular cylinder is $576\pi \text{ in.}^3$.
Surface area of the closed right circular cylinder is $272\pi \text{ in.}^2$.
Work Step by Step
The given values are
Radius $r=8\text{ in.}$
Height $h=9\text{ in.}$
Volume of the closed right circular cylinder $V=\pi r^2h$.
Substitute the given values.
$V=\pi (8\text{ in.})^2(9\text{ in.})$
$V=576\pi \text{ in.}^3$
Hence, the volume of the closed right circular cylinder is $576\pi \text{ in.}^3$.
Surface area of the closed right circular cylinder $S=2\pi r^2+2\pi rh$.
Substitute the given values.
$S=2\pi (8\text{ in.})^2+2\pi (8\text{ in.})(9\text{ in.})$
$S=128\pi \text{ in.}^2 +144\pi \text{ in.}^2$
$S=272\pi \text{ in.}^2$
Hence, the surface area of the closed right circular cylinder is $272\pi \text{ in.}^2$.
