Answer
Volume of the closed rectangular box is $224$ cubic feet.
Surface area of the closed rectangular box is $232$ square feet.
Work Step by Step
The given values are
Length $l=8\; ft$
Width $w=4\;ft$
Height $h=7\;ft$
The volume $V$ of a closed rectangular box is given by the formula $V=lwh$ where $l$ is its length, $w$ is its width, and $h$ is its height.
Substitute the given values to obtain:
$V=(8\text{ ft})(4\text{ ft})(7\text{ ft})$
$V=224 \text{ ft}^3$
Hence, the volume of the closed rectangular box is $224$ cubic feet.
The surface area $S$ of a closed rectangular box is given by the formula $S=2lh+2wh+2lw$ where $l$ is its length, $w$ is its width, and $h$ is its height.
Substitute the given values to obtain:
$S=2(8\text{ ft})(7\text{ ft})+2(4\text{ ft})(7\text{ ft})+2(8\text{ ft})(4\text{ ft})$
$S=112 \text{ ft}^2+56\text{ ft}^2+64\text{ ft}^2$
$S=232\text{ ft}^2$
Hence, the surface area of the closed rectangular box is $232$ square feet.
