Answer
Volume is $648\pi \text{ in.}^3$.
Surface area is $306\pi \text{ in.}^2$.
Work Step by Step
The given values are
Radius $r=9\text{ in.}$
Height $h=8\text{ in.}$
Volume of the closed right circular cylinder $V=\pi r^2h$.
Substitute the given values.
$V=\pi (9\text{ in.})^2(8\text{ in.})$
$V=648\pi \text{ in.}^3$
Hence, the volume of the closed right circular cylinder is $648\pi \text{ in.}^3$.
Surface area of the closed right circular cylinder $S=2\pi r^2+2\pi rh$.
Substitute the given values.
$S=2\pi (9\text{ in.})^2+2\pi (9\text{ in.})(8\text{ in.})$
$S=162\pi \text{ in.}^2 +144\pi \text{in.}^2$
$S=306\pi \text{ in.}^2$
Hence, the surface area of the closed right circular cylinder is $306\pi \text{ in.}^2$.
