Answer
$$ 6\cos \left(t\right)\sin \left(t\right)-8sint$$
Work Step by Step
Simplifying the expression, we obtain:
$$2\cos \left(t\right)\left(3\sin \left(t\right)-4\tan \left(t\right)\right)$$
Since tangent equals $\frac{sint}{cost}$, it follows:
$$2\cdot \:3\cos \left(t\right)\sin \left(t\right)-2\cdot \:4\cos \left(t\right)\tan \left(t\right)
\\ 6\cos \left(t\right)\sin \left(t\right)-8\cos \left(t\right)\tan \left(t\right) \\ 6\cos \left(t\right)\sin \left(t\right)-8sint$$
