Answer
$$6\cos \left(t\right)-14 sint$$
Work Step by Step
Simplifying the expression, we obtain:
$$2\cos \left(t\right)\left(3-7\tan \left(t\right)\right)$$
Since tangent equals $\frac{sint}{cost}$, it follows:
$$6\cos \left(t\right)-14\cos \left(t\right)\tan \left(t\right) \\ 6\cos \left(t\right)-14 sint$$