Answer
$
s(w)=(v-4 t+k v) \cdot \quad j^w
$
Work Step by Step
We know that $w$, is the independent variable,and is in the exponent, so this can not be a linear function. It must an exponential function. We want to write it in the form $s(w)=a b^w$ :
$$
\begin{aligned}
s(w) & =v j^w-4 t j^w+k v j^w \\
& =\underbrace{(v-4 t+k v)}_a \cdot \underbrace{j^w}_{b^w},
\end{aligned}
$$ So $$
a=v-4 t+k v, b=j \text {. }
$$
