Answer
$
\begin{aligned}
r(v) =\underbrace{-4 t j^w}_b+\underbrace{\left(j^w+k j^w\right)}_m v,
\end{aligned}
$
Work Step by Step
We know that $v$ is the independent variable, so this is not an exponential function.It must be linear. We want to it in the form $r(v)=b+m v$ :
$$
\begin{aligned}
r(v) & =v j^w-4 t j^w+k v j^w \\
& =\underbrace{-4 t j^w}_b+\underbrace{\left(j^w+k j^w\right)}_m v,
\end{aligned}
$$ $$
\text { so } b=-4 t j^w, m=j^w+k j^w
$$
