Answer
$
p(x)=\frac{7 \sqrt{e}}{20} e^x
$
Work Step by Step
Rewrite the function as follows:
$$
p(x)=\frac{7 e^{6 x} \cdot \sqrt{e} \cdot\left(2 e^x\right)^{-1}}{10 e^{4 x}}=\frac{7 \cdot \sqrt{e} \cdot 2^{-1}}{10} e^{(6 x-x-4 x)}=\frac{7 \sqrt{e}}{20} e^x
$$ where $a=\frac{7 \sqrt{e}}{20}$ and $k=1$
