Functions Modeling Change: A Preparation for Calculus, 5th Edition

Published by Wiley
ISBN 10: 1118583191
ISBN 13: 978-1-11858-319-7

Chapter 4 - Exponential Functions - 4.4 Applications to Compound Interest - Exercises and Problems for Section 4.4 - Exercises and Problems - Page 167: 2

Answer

a) $\$ 1270.24$ b) $\$ 1271.01$ c) $\$ 1271.22$

Work Step by Step

(a) The nominal interest rate is $8 \%$, so the interest rate per month is $0.08 / 12$. Therefore, at the end of 3 years is Balance $$S= 1000\left(1+\frac{0.08}{12}\right)^{36}=\$ 1270.24$$ (b) There are 52 weeks in a year, so the interest rate per week is $0.08 / 52$. At the end of $52 \times 3=156$ weeks. $$S= 1000\left(1+\frac{0.08}{52}\right)^{156}=\$ 1271.01$$ (c) The interest rate per day is $0.08 / 365$. At the end of $3 \times 365= 1095$ days $$S= 1000\left(1+\frac{0.08}{365}\right)^{1095}=\$ 1271.22$$
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