Answer
a) $\$ 18,655.38$
b) $\$ 16,771.93$
c) $\$ 18,520.84$
Work Step by Step
Let the initial investment be $P $, and the final value be $F=25000 $.
a) We know that $n= 1$ and $t= 6$ for this problem. It follows that
$$
\begin{aligned}
P& =F\left( 1+\frac{r}{n}\right)^{-nt} \\
& = 25000\left( 1+\frac{0.05}{1}\right)^{-6}\\
& = \$18,655.38
\end{aligned}
$$
b) We know that $n= 12$ and $t= 6$ for this problem. It follows that
$$
\begin{aligned}
P& = 25000\left( 1+\frac{0.05}{12}\right)^{-96}\\
& = \$16,771.93
\end{aligned}
$$
c) We know that $n= 365$ and $t= 6$ for this problem. It follows that
$$
\begin{aligned}
P& = 25000\left( 1+\frac{0.05}{365}\right)^{-2190}\\
& = \$18,520.84.
\end{aligned}
$$
