Functions Modeling Change: A Preparation for Calculus, 5th Edition

Published by Wiley
ISBN 10: 1118583191
ISBN 13: 978-1-11858-319-7

Chapter 4 - Exponential Functions - 4.4 Applications to Compound Interest - Exercises and Problems for Section 4.4 - Exercises and Problems - Page 167: 18

Answer

$1.628 \%$

Work Step by Step

Let the initial investment be $P = 850$, and the final value be $F=1000 $. We know that $$ \begin{aligned} F& =P\left( 1+\frac{r}{n}\right)^{nt} \\ \end{aligned} $$ where $n= 4$ and $t= 10$ for this problem. It follows that $$ \begin{aligned} 850\left( 1+\frac{r}{4}\right)^{40}& =1000\\ \left( 1+\frac{r}{4}\right)^{40}& =\frac{1000}{850}\\ 1+\frac{r}{4}& = \left(\frac{100}{85}\right)^{\frac{1}{40}}\\ r&= 4\left(\frac{100}{85}\right)^{\frac{1}{40}}-4\\ r&= 0.01628=1.628\%\\ \end{aligned} $$ The nominal interest rate is $1.628 \%$.
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