Functions Modeling Change: A Preparation for Calculus, 5th Edition

Published by Wiley
ISBN 10: 1118583191
ISBN 13: 978-1-11858-319-7

Chapter 2 - Functions - Review Exercises and Problems for Chapter Two - Page 110: 48

Answer

$V=6\pi$ cubic inches

Work Step by Step

Plugging in values of $r=3 in.$ and $h=2 in.$ yields $$V=\frac{1}{3}\pi (3 in.)^2(2 in.)$$ $$V=\frac{1}{3} \pi (9 in^2)(2 in)$$ $$V = 6\pi in.^3$$
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