Answer
The inverse of the function is
$g^{-1}(y)=(y-1)^2$
Work Step by Step
Since $y=\sqrt{t}+1$, solving for $t$ gives
$$
\begin{aligned}
\sqrt{t}+1 & =y \\
\sqrt{t} & =y-1 \\
t & =(y-1)^2 \\
g^{-1}(y) & =(y-1)^2 .
\end{aligned}
$$
Functions Modeling Change: A Preparation for Calculus, 5th Edition
by Connally, Eric; Hughes-Hallett, Deborah; Gleason, Andrew M.; Cheifetz, Phil C.
Published by
Wiley
ISBN 10:
1118583191
ISBN 13:
978-1-11858-319-7
Chapter 2 - Functions - Review Exercises and Problems for Chapter Two - Page 110: 38
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