Answer
$f(g(x))=3 x^3-4$
Work Step by Step
Given $f(x)=3 x-7$ and $g(x)=x^3+1$.
We have
$$
f(g(x))=f\left(x^3+1\right)=3\left(x^3+1\right)-7=3 x^3-4
$$
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