Answer
$71.57^{\circ}$
Work Step by Step
We know that:
$\cos \theta=\dfrac{w \cdot v}{|w| |v|}\\ =\dfrac{(i-j) (2i+j)}{|i-j| |2i+j|}\\=\dfrac{1}{\sqrt 2 \sqrt 5}\\=\dfrac{1}{\sqrt {10}}$
Now, $\theta = \cos^{-1} \dfrac{1}{\sqrt {10}} \approx 71.57^{\circ}$