Thinking Mathematically (6th Edition)

Published by Pearson
ISBN 10: 0321867327
ISBN 13: 978-0-32186-732-2

Chapter 7 - Algebra: Graphs, Functions, and Linear Systems - 7.3 Systems of Linear Equations in Two Variables - Exercise Set 7.3 - Page 444: 4

Answer

The ordered pair is not the solution of the system.

Work Step by Step

Step 1: Check the order of pair \[\left( 8,5 \right)\]for the equation,\[5x-4y=20\]. Now, substitute \[x=8\]and \[y=5\]in the equation, then solve. \[\begin{align} & 5\times 8-4\times 5=20 \\ & 40-20=20 \\ & 20=20 \end{align}\] From the above calculation,the left-hand and right-hand sides are equal. So, the order of pair satisfied this equation. Step 2: Check the order of pair \[\left( 8,5 \right)\]for the equation,\[3y=2x+1\]. Now, substitute \[x=8\]and \[y=5\]in the equation, then solve. \[\begin{align} & 3\times 5=2\times 8+1 \\ & 15\ne 17 \\ \end{align}\] From the above calculation,the left-hand and right-hand sides are not equal. So, the order of pair does not satisfy this equation. Hence, the order of the pair \[\left( 8,5 \right)\]does not satisfy the system equations. So, the ordered pair is not the solution of the system. The ordered pair is not the solution of the system.
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