Thinking Mathematically (6th Edition)

Published by Pearson
ISBN 10: 0321867327
ISBN 13: 978-0-32186-732-2

Chapter 7 - Algebra: Graphs, Functions, and Linear Systems - 7.3 Systems of Linear Equations in Two Variables - Exercise Set 7.3 - Page 444: 1

Answer

the ordered pair \[\left( 2,3 \right)\] is a solution of the system of equations.

Work Step by Step

Multiply equation second with \[-1\]and add it with first equation.Thus, \[\begin{align} & \left( x-5y=-13 \right)\times -1 \\ & -x+5y=13 \\ \end{align}\] Now, add first and above equation to eliminate\[x\]as: \[\begin{align} & \left( -x+5y \right)+\left( x+3y \right)=13+11 \\ & 5y+3y=24 \\ & 8y=24 \\ & y=3 \end{align}\] Now, substitute the value of\[y=3\]in the first equation to get the value of \[x\]as: \[\begin{align} & x+3\left( 3 \right)=11 \\ & x+9=11 \\ & x=2 \end{align}\] Hence, the ordered pair \[\left( 2,3 \right)\] is a solution of the system of equations.
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