Thinking Mathematically (6th Edition)

Published by Pearson
ISBN 10: 0321867327
ISBN 13: 978-0-32186-732-2

Chapter 6 - Algebra: Equations and Inequalities - 6.5 Quadratic Equations - Exercise Set 6.5 - Page 400: 81

Answer

$1+\sqrt7$

Work Step by Step

Our equation is: $x^2-(6+2x)=0\\x^2-2x-6=0\\(x-1)^2-1-6=0\\(x-1)^2=7$ Because $x$ is positive: $x-1=\sqrt7\\x=1+\sqrt7$
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