Thinking Mathematically (6th Edition)

Published by Pearson
ISBN 10: 0321867327
ISBN 13: 978-0-32186-732-2

Chapter 6 - Algebra: Equations and Inequalities - 6.2 Linear Equations in One Variable and Proportions - Exercise Set 6.2 - Page 362: 85


No Solution Using set notation: { }

Work Step by Step

To solve the equation: $\frac{x}{3}$ + 2 = $\frac{x}{3}$ We start by subtracting $\frac{x}{3}$ from both sides of the equation. $\frac{x}{3}$ - $\frac{x}{3}$ + 2 = $\frac{x}{3}$ - $\frac{x}{3}$ Performing the subtraction, we get 2 = 0. Since 2 = 0 is not a true statement and there is no way they can be made equal, we have no solution.
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