Thinking Mathematically (6th Edition)

Published by Pearson
ISBN 10: 0321867327
ISBN 13: 978-0-32186-732-2

Chapter 6 - Algebra: Equations and Inequalities - 6.2 Linear Equations in One Variable and Proportions - Exercise Set 6.2: 14

Answer

{14}

Work Step by Step

3x +8 = 50 Step 1: Subtract 8 from both the sides 3x +8 - 8 = 50 - 8 Step 2: Simplify 3x = 42 Step 3: Divide both the sides by 3 $\frac{3x}{3}$ = $\frac{42}{3}$ Step 4: Simplify x = 14 Now we check the proposed solution, 14, by replacing x with 14 in the original equation. Step 1: the original equation 3x +8 =50 Step2: Substitute 14 for x 3.14 + 8 = 50 Step 3: Multiply 3.14 = 42 42 + 8 = 50 Step 4: Add 42 +8 = 50 50 =50 Since the check results in true statement, we conclude that the solution set of the given equation is {14}
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