Thinking Mathematically (6th Edition)

Published by Pearson
ISBN 10: 0321867327
ISBN 13: 978-0-32186-732-2

Chapter 6 - Algebra: Equations and Inequalities - 6.2 Linear Equations in One Variable and Proportions - Exercise Set 6.2: 5

Answer

{12}.

Work Step by Step

$\frac{x}{3}$ = 4 Step 1: Multiply both the sides by 3 $\frac{x}{3}$ x 3 = 4 x 3 Step 2: Simplify x= 12 Now we check the proposed solution, 12, by replacing x with 12 in the original equation. Step 1: the original equation $\frac{x}{3}$ = 4 Step2: Substitute 12 for x $\frac{12}{3}$ = 4 Step 3: Solve $\frac{12}{3}$ =4 4=4 Since the check results in true statement, we conclude that the solution set of the given equation is {12}.
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